I have a find that look likes this: @values = UdidValue.find(:all, :conditions => ['udid_id = ?', x.id], :order => 'value ASC') The problem is that 'value' could be a street address, for example, numbers. So, when I do the :order if they are strings the get order wonderfully, but in one case I have values that are numbers, for example, 234, 233, 219, 25, 199, which get order as 199, 25, 219, 233, 234. Which is not what I want. I would like to order as 25, 199, 219, 233, 234. Is there a way to get the order to order properly regardless if it is a number of string? Thanks, -S
on 2009-04-08 20:51
on 2009-04-08 21:19
> 233, 234. > > Is there a way to get the order to order properly regardless if it > is a > number of string? Thanks, Google for "natural sort" for your particular database. If mysql, maybe... http://blog.feedmarker.com/2006/02/01/how-to-do-na...