Forum: Ruby on Rails Help with Code Tweaking

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Lin W. (Guest)
on 2009-04-03 14:01
scenario : select distinct years from members and their respective
record count of that particular year.

eg:  [{year = 2008 , count = 45123},{year = 2007 , count = 12332} ]

previously , i was using "select distinct tochar(datetime)" , it ended
up taking quite a while to fetch the records so i switched to this code.

relationship group 1 : N members

rootgroup is a pretched group

member = root_group.members.find(:all,
      :select => "max(datetime) as maxdate,min(datetime) as mindate"

return member.mindate.year.upto(member.maxdate.year).inject({}) do

              #return hash with year and member count for that year

              compare_date =,1,1)

              {year , root_group.members.find(
               :conditions => [ "datetime >= ? AND datetime < ?",
                                 compare_date + 1.year ],
                                :select => 'count(*)')}

any ideas on how to tweak it ?

it really looks quite clumsy at the moment
and iam repeating the code for drilling into the months and days ,
it really feels like bad practice.

Philip H. (Guest)
on 2009-04-03 21:03
(Received via mailing list)
Why not use something like this:

=# select count(*), date_part('minute', created_at) as min from toys
group by min;
  count | min
   4008 |  36
   5239 |  37
   4496 |  38
(3 rows)

Replacing "date_part" with whatever date function your database
supports to return the year.  In my example I used minutes only
because all the data was created at the same time.

Worth benchmarking at least.
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