Search latest version of file in directory

Ruby
1

Hi, I have a directory full of files and want to get the newest version
of each out of the directory. The files look like below. Please tell me
if you know a way to pull out the latest version of each. Thanks

34_web1_no2_09202008.txt
34_web1_no2_09212008.txt <–want to pull out this latest version
34_web2_no3_10122008.txt
34_web2_no3_10132008.txt <–want to pull out this latest version

snippet*************************************

newsortfile = Dir[“C:/Status2/*.html”].map{|@f|
[@f,File.mtime(@f)]}.sort_by{|@i|@i[1]}
@NewestFile = @i[1]

Dir.entries(“C:/Status2/”).each do |filename|
if File.mtime(“C:/Status2/”+filename) == @NewestFile then
puts filename
end
end

2

On 09.02.2009 20:46, Mmcolli00 Mom wrote:

newsortfile = Dir[“C:/Status2/*.html”].map{|@f|
[@f,File.mtime(@f)]}.sort_by{|@i|@i[1]}
@NewestFile = @i[1]

Dir.entries(“C:/Status2/”).each do |filename|
if File.mtime(“C:/Status2/”+filename) == @NewestFile then
puts filename
end
end

This is how I’d approach this:

dir = “C:/Status2”
files = Hash.new {|h,k| h[k] = []}

Dir[File.join(dir, “*.txt”)].each do |f|
files[f[/^\d+_web\d+_no\d+/]] << File.join(dir, f)
end

files.each do |k,v|
puts v.sort_by! {|f| File.mtime(f)}.last
end

Cheers

robert

3

Mmcolli00 Mom wrote:

snippet*************************************

newsortfile = Dir[“C:/Status2/*.html”].map{|@f|
[@f,File.mtime(@f)]}.sort_by{|@i|@i[1]}
@NewestFile = @i[1]

Dir.entries(“C:/Status2/”).each do |filename|
if File.mtime(“C:/Status2/”+filename) == @NewestFile then
puts filename
end
end

rx = /^.*_no\d+/
puts DATA.readlines.sort_by{|x| [x[rx],x[-8,8],x] }.
inject(nil){|prev,x|
puts prev if prev && prev[ rx ] != x[ rx ] ; x }

END
34_web1_no2_12202007.txt
34_web1_no2_09202008.txt
34_web1_no2_09212008.txt
34_web2_no3_12122007.txt
34_web2_no3_10122008.txt
34_web2_no3_10132008.txt