Forum: Ruby difference between *options and options

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Sijo k. (Guest)
on 2009-01-07 07:05
   I saw below code

options = { :a => 1, :b => 2, :c => 3 }
rejects = Hash[* { |k, v| k == :b && options.delete(k)

   In the above if I use options insted of *options what is actually
happening..I would like to know their difference What actually means

Thanks in advance
Justin C. (Guest)
on 2009-01-07 07:58
(Received via mailing list)
Sijo Kg wrote:
> Thanks in advance
> Sijo

This code might be a little deceptive, but if you look closely
" { |k, v| k == :b && options.delete(k)}.flatten" is just
creating an array out of selected keys and values. After that, the splat
operator (*) is being used to turn the array into parameters for the
Hash.[] function...which turns it back into a hash. Tada!

I note that in Ruby 1.9.1, Hash#select returns a hash, making this
weirdness unnecessary.

More about splat, including this particular use:

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