Forum: Ruby A proper Ruby way to call a procedure by name

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John S. (Guest)
on 2008-12-14 16:06
I know how to do this using a case statement but I want to know if
there's a more Rubyesque way of doing things.

I'm screen scraping from a lot of different sources. They all have much
same data but it's presented in different ways with different access
methods. I use scRubyt to do the scraping and define most of the setup
for each way of presenting things in hashes which are read in from yaml
files. That way I can nearly DRY everything up into a few simple Ruby
routines with all the differences between the websites extracted into
data files.

But there's one area I'm not satisfied with because some cases are so
different from the others that I have to write special routines just
for them. That's ok and I can name the routines to be used for those
cases in the yaml file. Then when the yaml config file is read in I can
use a switch statement to tell me how to process the data from each site
along the lines of

result = case value
   when name1_from_yaml: result1(param1,param2)
   when name2_from_yaml: result2(param1,param2)

which is fine and dandy but what I really want to do is to be able to
put the name of the function to call into the yaml data file and then
somehow get to

result = function_named_in_yaml_file(param1,param2)

How do I do this in Ruby? In other words I want a string or symbol to
invoke a procedure without going via a case statement.


John S.
Tim H. (Guest)
on 2008-12-14 16:53
(Received via mailing list)
John S. wrote:
>    etc
> Ta
> John S.

ri Object#__send__

obj.__send__(method_name, arg1, arg2...)
John S. (Guest)
on 2008-12-15 14:37

OK, thanks for that. I knew it had to be simple

>> John S.
> ri Object#__send__
> obj.__send__(method_name, arg1, arg2...)
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