Hi,
Are lazy requires generally a good idea
def require_files(path)
dir = File.dirname(FILE)
Dir[File.expand_path("#{dir}/#{path}")].uniq.each do |file|
require file
end
end
?
Thanks
Aidy
Hi,
Are lazy requires generally a good idea
def require_files(path)
dir = File.dirname(FILE)
Dir[File.expand_path("#{dir}/#{path}")].uniq.each do |file|
require file
end
end
?
Thanks
Aidy
On Nov 17, 6:36 am, aidy [email protected] wrote:
Hi,
Are lazy requires generally a good idea
def require_files(path)
dir = File.dirname(FILE)
Dir[File.expand_path(“#{dir}/#{path}”)].uniq.each do |file|
require file
end
end
Why do you call that lazy? Do you mean “dynamic” requires?
Define good.
Hi,
On Nov 17, 2008, at 5:36 AM, aidy wrote:
Are lazy requires generally a good idea
def require_files(path)
dir = File.dirname(FILE)
Dir[File.expand_path("#{dir}/#{path}")].uniq.each do |file|
require file
end
end?
I also am not sure what you mean by “lazy” or “good”, but offer this:
Requiring a full path can become messy with double requires if you
require the same file anywhere else in your project. It is sometimes
preferred to add the dir to your load paths and require the file’s
base name, instead.
Other things to consider
Stephen
aidy wrote:
Hi,
Are lazy requires generally a good idea
def require_files(path)
dir = File.dirname(FILE)
Dir[File.expand_path("#{dir}/#{path}")].uniq.each do |file|
require file
end
end
It’s certainly accepted practice, but with all things you need to ask if
it’s necessary.
If you know the files in the path you want, it’s much more reliable to
specify them.
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