My question has to do with the diagram on page 12 of "Advanced Rails". It arises from the following structure: module A; end; module B; include A; end module C; include A; end class D; include B; include C; end (This would be a diamond-shaped hierarchy if inheritance were used.) Now picture a similar structure, except without a common ancestor: module A1; end; module A2; end; module B; include A1; end module C; include A2; end class D; include C; include B; end d = D.new When a message is sent to d, that method is searched for in the following order: B, A1, C, A2. My question is how this is implemented in terms of 'klass' and 'super' as described in the book. First, the klass pointer from d takes us to D, whose m_tbl is searched. Then D's super pointer takes us to the proxy for the B module. That proxy's m_tbl pointer points to the B methods which are searched. Then B's super pointer takes us to B's proxy for the A1 module, which causes A1's methods to be search. Here's my problem. If A1 doesn't contain the method, what causes the search to backtrack to the B proxy and follow its super pointer to the C proxy? This "backtracking" seems counter to the purported "linear" lookup order. (This is just a conceptual problem for me - it's obvious what the lookup order is, and it's easy to verify.) The best I can come up with is that the process is this: 1. Look for the method in D 2. If not found, follow the super and look for the method in the B proxy 3. If not found, follow the super and look for the method in the C proxy 4. If not found, follow the super and look for the method in the A2 proxy 5. If not found, give up However, "look for the method in the B proxy" expands to 2a. Look for the method in B 2b. If not found, follow the super and look for the method in the A1 proxy 2c. If not found, give up (which takes us back to #3 above That sounds right. :) But then I'm confused by the use of the klass pointers in the diagram. They seem to imply that when the lookup follows the super from D to the B proxy, that B is a non-class object and hence its klass pointer is used to find its methods. That would imply that the B proxy is an object of the B class, which doesn't sound right. Is the klass pointer actually used to find the B proxy's methods? Or is it just the case that the B proxy class object and the B class object contain the same m_tbl pointer? If so, what (if anything) is the klass pointer between the proxy and the class object used for? I think the best answers to this question will come from people who have the "Advanced Rails" book to hand. I've searched pretty far and wide and simply haven't found an explanation of how method lookup passes from an included module to a module that's included in that one. I'm probably making a conceptual mountain of a molehill, but any clarification (other than "read the code!") would be appreciated. ///ark
on 15.05.2008 04:29
on 15.05.2008 06:10
Mark Wilden wrote:
> My question has to do with the diagram on page 12 of "Advanced Rails".
Then why wouldn't you post your question in a Rails forum??!
on 15.05.2008 07:06
On May 14, 2008, at 8:29 PM, Mark Wilden wrote: > > Here's my problem. If A1 doesn't contain the method, what causes the > search to backtrack to the B proxy and follow its super pointer to > the C proxy? This "backtracking" seems counter to the purported > "linear" lookup order. (This is just a conceptual problem for me - > it's obvious what the lookup order is, and it's easy to verify.) as each module in included in the target, it's entire lookup chain is added to that target - therefore no 'backtracking' is required, we just end up with a long line that, when followed, happens to give the appearance if backtracking. a @ http://codeforpeople.com/
on 15.05.2008 12:54
On Thu, May 15, 2008 at 12:10 AM, 7stud -- <bbxx789_05ss@yahoo.com> wrote: > Mark Wilden wrote: >> My question has to do with the diagram on page 12 of "Advanced Rails". > > Then why wouldn't you post your question in a Rails forum??! Because, if you read past he first line, you'd realize that it is definitely a Ruby and not a Rails question. -- Rick DeNatale My blog on Ruby http://talklikeaduck.denhaven2.com/
on 15.05.2008 17:00
On May 14, 2008, at 10:05 PM, ara.t.howard wrote: >> Here's my problem. If A1 doesn't contain the method, what causes >> the search to backtrack to the B proxy and follow its super pointer >> to the C proxy? This "backtracking" seems counter to the purported >> "linear" lookup order. (This is just a conceptual problem for me - >> it's obvious what the lookup order is, and it's easy to verify.) > > as each module in included in the target, it's entire lookup chain > is added to that target - therefore no 'backtracking' is required, > we just end up with a long line that, when followed, happens to give > the appearance if backtracking. I do understand that that's how it works in practice. I was trying to understand the process in terms of its implementation via proxies, klass, super and m_tbl. If it were truly implemented as a single long chain, then that would require (in my example) that the A2 proxy's super points to the B proxy. Hmmm....I wonder if that's indeed the case, as you imply? ///ark
on 15.05.2008 22:25
On Thu, May 15, 2008 at 10:59 AM, Mark Wilden <mark@mwilden.com> wrote: >> up with a long line that, when followed, happens to give the appearance if >> backtracking. > > I do understand that that's how it works in practice. I was trying to > understand the process in terms of its implementation via proxies, klass, > super and m_tbl. If it were truly implemented as a single long chain, then > that would require (in my example) that the A2 proxy's super points to the B > proxy. Hmmm....I wonder if that's indeed the case, as you imply? module A1; end; module A2; end; module B; include A1; end module C; include A2; end class D; include C; include B; end results in the chains: A1 A1 B -> proxy1(A1) C-> proxy2(A2) D->proxy5(B)->proxy6(A1)->proxy3(C)->proxy4(A2)->Object->proxy0(Kernel) where proxyn indicates the nth module-proxy in creation order. When you include a module in a class, the current chain is searched to see if the module is already included and doesn't re-include it, and includes in a given class or module executed later are inserted before earlier includes in the same class or module, so the chain for the original set of modules and classes: module A; end; module B; include A; end module C; include A; end class D; include B; include C; end The chain for D looks like this: D->proxy(C)->proxy(B)->proxy(A)->Object->proxy(Kernel) This can lead to some small surprises for some people. Ruby doesn't include a proxy to a given module more than once in any inheritance chain, because of the way it implements finding overridden methods when resolving super. MRI doesn't keep track of the place in the chain where it found the currently executing method, so to find the method to be invoked for super, it searches again from the start until it finds the current METHOD, then searches from the next link in the chain. If a module proxy were repeated then this wouldn't work because some cases would loop. See the two articles below: http://talklikeaduck.denhaven2.com/articles/2007/06/02/chain-chain-chain http://talklikeaduck.denhaven2.com/articles/2007/11/03/a-chat-with-matz-classs-variable-reversion-and-a-mystery-explained -- Rick DeNatale My blog on Ruby http://talklikeaduck.denhaven2.com/